UVa OJ 108 – Maximum Sum
Problem link https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=44 Hints Violence Solution code
Problem link https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=44 Hints Violence Solution code
Problem link https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=14&page=show_problem&problem=1141 Hints Attention to accuracy issues Solution code
Problem link https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=12&page=show_problem&problem=941 Hints Floyd–Warshall algorithm Solution code
Problem link https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=42 Hints Beginning of Chapter 13th in Elementary Number Theory and its applications 6ed, Kenneth H. Rosen, 2011 Solution code
Problem link https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=41 Solution code
Problem link https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=40 Hints Floyd-Warshall algorithm Solution code Bibliography JeraKrs. uva 104 – Arbitrage(最短路Floyd). CSDN blog. 2013-10-13 16:20:27 Ruslan Ledesma-Garza, Arbitrage, Published on May 26, 2016, edited on Oct 25, 2016
Problem link: https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=39 Hints DFS+DP记忆化搜索 Solution code
Problem link: https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=38 Solution code
Problem link: https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=37 Hints Simulation Solution code 1: Solution code 2
Browse problem UVa Online Judge. 10714 – Ants. PKU JudgeOnline. No. 1852 – Ants Solution Thinking If all the ants are going to the nearest end of the pole, it is easy to find the earliest time needed. 只要所有的蚂蚁都走到杆的最近端,求出所需的最短时间就很简单。 Find the latest time (找出最长时间) If there are two or more […]